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x^2+22.98x-4.2=0
a = 1; b = 22.98; c = -4.2;
Δ = b2-4ac
Δ = 22.982-4·1·(-4.2)
Δ = 544.8804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22.98)-\sqrt{544.8804}}{2*1}=\frac{-22.98-\sqrt{544.8804}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22.98)+\sqrt{544.8804}}{2*1}=\frac{-22.98+\sqrt{544.8804}}{2} $
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